Need help: Recipe for oily winstrol

I made my 1st winstrol 50mg in oil by Guaiacol. it smells unbelievable strong and bitter. anyways i made 20ml @ 50MG/ml by the following routine and standard materials:

powder= 1 gram
gso= 17 ml
ba = 0.2 ml
guaiacol = 2 ml

and NOW want to use from 4 gram powder. basically 4g is 4 times of the above material, so should be :

powder= 4 x 1g =4g
gso = 17ml x 4 = 68ml
ba = 4 x 0.2ml = 0.8ml
guaiacol = 4 x 2ml = 8ml

on the other hand when i use the calculate table i got the following results which is quite different:


i was wondering if anybody knows why this contrast has been happened.

Thanks!

any help?

Because the calculator is using an actual displacement number

bump for recent stanozolol in oil recipe questions no idea if this helps or not

You have to have the actual physical weight displacement. The calculator is old and based on estimated chemical weight.

I believe when in doubt add more sterile oil, if its to thick add BB. That's a opinion by the way.

Powderguy said:

You have to have the actual physical weight displacement. The calculator is old and based on estimated chemical weight.

I believe when in doubt add more sterile oil, if its to thick add BB. That's a opinion by the way.

Click to expand...

Thanks for your reply Powderguy!

Do you aware of new calculator by any chance?

NO, making one would be a waste. You can look up all displacements on the web. Every chemical structure has a molecular weight to establish displacement. Stan is light and has approx. the same weight as Dianabol powder.

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Stan is approx. 0.962 on your displacement and has a molecule weight of 328.49. hope that helps.

good to c you back helping with steroid home brew section.

Thanks brotha..had to take a break and get back on track with things.